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प्रश्न
A diverging mirror of radius of curvature 40 cm forms an image which is half the height of the object. Find the object and image positions.
उत्तर
The mirror is convex.
⇒`1/20=(-1)/u`
⇒`u=-20cm`
⇒`v=-((-20))/2`
⇒`v=10 cm`
Notes
`1/f=1/u-2/u(-1)/u`
⇒`1/20=(-1)/u`
⇒`u=-20cm`
⇒`v=-((-20))/2`
⇒`v=10 cm`
संबंधित प्रश्न
Suppose you have focused on a screen the image of candle flame placed at the farthest end of the laboratory table using a convex lens. If your teacher suggests you to focus the parallel rays of the sun, reaching your laboratory table, on the same screen, what you are expected to do is to move the:
(a) lens slightly towards the screen
(b) lens slightly away from the screen
(c) lens slightly towards the sun
(d) lens and screen both towards the sun
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(a) −4 cm
(b) −400 mm
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