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प्रश्न
A diverging mirror of radius of curvature 40 cm forms an image which is half the height of the object. Find the object and image positions.
उत्तर
The mirror is convex.
⇒`1/20=(-1)/u`
⇒`u=-20cm`
⇒`v=-((-20))/2`
⇒`v=10 cm`
Notes
`1/f=1/u-2/u(-1)/u`
⇒`1/20=(-1)/u`
⇒`u=-20cm`
⇒`v=-((-20))/2`
⇒`v=10 cm`
संबंधित प्रश्न
Define focal length of a divergent lens.
An image formed by a concave ______ cannot be obtained on a screen.
A concave lens always forms a virtual image.
State two differences between a convex and a concave lens.
Write the new Cartesian sign convention for spherical lenses.
Two lenses A and B have power of (i) +2D and (ii) −4D respectively. What is the nature and focal length of each lens?
If a spherical lens has a power of, −0.25 D, the focal length of this lens will be :
(a) −4 cm
(b) −400 mm
(c) −4 m
(d) −40 cm
What are the three principal rays that are drawn to construct the ray diagram for the image formed by a lens? Draw diagrams to support your answer.
Complete the ray diagram to show how the rays pass into and out of the lens?
Complete the following table for convex lens:
| Sr. No. | Position of the object | Position of the image | Nature of the image |
| 1. | Beyond 2F1 | __________________ | ________________________ |
| 2. | __________________ | At infinity | ________________________ |
| 3. | __________________ | __________________ | Real, inverted and enlarged |
