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प्रश्न
A farsighted person cannot see objects placed closer to 50 cm. Find the power of the lens needed to see the objects at 20 cm.
संक्षेप में उत्तर
उत्तर
Here ,
u = – 20 cm and v = – 50 cm
The lens formula is given by
`1/v - 1/u = 1/f `
On putting the values, we get:
`1/f = 1/((-50)) - 1/((-20))`
= `3/100`
`=> f = 100/3 text/" cm" = 1/3 text/" m"`
∴ Power of the lens =`1/f = 3 D`
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