Advertisements
Advertisements
प्रश्न
A force of 10 N acts on a body of mass 5 kg. Find the acceleration produced.
उत्तर
Force, F = 10 N
Mass, m = 5kg
Acceleration, a = F/m [ From Newton's second law]
Or, a = (10/5) ms-2
Or, a = 2 ms-2
APPEARS IN
संबंधित प्रश्न
A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.
The values of g at six distances A, B, C, D, E and F from the surface of the earth are found to be 3.08 m/s2, 9.23 m/s2, 0.57 m/s2, 7.34 m/s2, 0.30 m/s2 and 1.49 m/s2, respectively.
(a) Arrange these values of g according to the increasing distances from the surface of the earth (keeping the value of g nearest to the surface of the earth first)
(b) If the value of distance F be 10000 km from the surface of the earth, state whether this distance is deep . inside the earth or high up in the sky. Give reason for your answer.
Name the force which pulled the apple off Isaac Newton’s tree.
Name the force which stops you falling through the floor.
The total energy of an object falling freely towards the ground ______.
The acceleration produced in a body by a force of given magnitude depends on
A force of 15 N acts on a body of mass 2 kg. Calculate the acceleration produced.
A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate : The acceleration produced by the force
Write acceleration due to gravity value on the surface of Earth.
Calculate the escape velocity on the surface of the moon given the mass and radius of the moon to be 7.34 × 1022 kg and 1.74 × 106 m respectively.
(Given: G = 6.67 × 10-11 Nm2/kg2)