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A gas mixture consists of 2.0 moles of oxygen and 4.0 moles of neon at temperature T. Neglecting all vibrational modes, calculate the total internal energy of the system. - Physics

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प्रश्न

A gas mixture consists of 2.0 moles of oxygen and 4.0 moles of neon at temperature T. Neglecting all vibrational modes, calculate the total internal energy of the system. (Oxygen has two rotational modes.)

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उत्तर

O2 is a diatomic gas having 5 degrees of freedom

Energy (total internal) per mole of the gas = `5/2` RT  ....`[(R = "Universal gas constant"),(T = "Temperature")]`

For 2 moles of the gas total internal energy = `2 xx 5/2` RT = 5 RT  .....(i)

Neon (Ne) is a monoatomic gas having 3 degrees of freedom

∴ Energy per mole = `3/2` RT

We have 4 moles of Ne

Hence, Energy = `4 xx 3/2` RT = 6 RT  .....(ii) [Using equations (i) and (iii)]

∴ Total energy = 5 RT + 6 RT

= 11 RT

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अध्याय 13: Kinetic Theory - Exercises [पृष्ठ ९४]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
अध्याय 13 Kinetic Theory
Exercises | Q 13.18 | पृष्ठ ९४
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