Question

A gas phase reaction has energy of activation 200 kJ mol⁻¹. If the frequency factor of the reaction is 1.6 × 10¹³ s⁻¹. Calculate the rate constant at 600 K. `("e"^-40.09 = 3.8 xx 10^-18)`

Answer 1

k = `"A e"^(-("E"_"a"/"RT"))`

k = `1.6 xx 10^13  "s"^-1 "e"^(((200 xx 103  "J" "mol"^-1)/(8.314  "JK"^-1  "mol"^-1 xx 600  "K")))`

k = `1.6 xx 10^13  "s"^-1  "e"^(-(40.1))`

k = 1.6 × 10¹³ s⁻¹ × 3.8 × 10⁻¹⁸

k = 6.21 × 10⁻⁵ s⁻¹