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Question
A gas phase reaction has energy of activation 200 kJ mol−1. If the frequency factor of the reaction is 1.6 × 1013 s−1. Calculate the rate constant at 600 K. `("e"^-40.09 = 3.8 xx 10^-18)`
Numerical
Solution
k = `"A e"^(-("E"_"a"/"RT"))`
k = `1.6 xx 10^13 "s"^-1 "e"^(((200 xx 103 "J" "mol"^-1)/(8.314 "JK"^-1 "mol"^-1 xx 600 "K")))`
k = `1.6 xx 10^13 "s"^-1 "e"^(-(40.1))`
k = 1.6 × 1013 s−1 × 3.8 × 10−18
k = 6.21 × 10−5 s−1
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Chapter 7: Chemical Kinetics - Evaluation [Page 230]
