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प्रश्न
A gaseous fuel contains H2=50% CH4=30% N2=2% CO=7% C2H4=3% C2H6=5% and water vapours=3%. Calculate weight and volume of air for 2m3 of the gas.
संख्यात्मक
उत्तर
Given:
H2=50% CH4=30% N2=2% CO=7% C2H4=3% C2H6=5% and water vapours=3%.
Required: Vol. and weight for complete combustion of 2 m3 of fuel.
| Constituents | Volume | Reaction | Vol. of oxygen required | ||
| % | m3 | ||||
| (i) | H2 | 50 | 0.5 | `H_2+1/2O_2=H_2O` | 0.5X0.5=0.25 |
| (ii) | CH4 | 30 | 0.3 | CH4+2O2=CO2+H2O | 0.3X2=0.6 |
| (iii) | CO | 7 | 0.07 | `CO+1/2O_2=CO_2` | 0.07X0.5=0.035 |
| (iv) | C2H4 | 3 | 0.03 | C2H4+3O2=2CO2+2H2O | 0.03X3=0.15 |
| (v) | C2H6 | 5 | 0.05 | C2H6+3.5O2=2CO2+3H2O | 0.05X3.5=0.175 |
Total Volume of O2 Required= 0.25+0.6+0.035+0.15+0.175= 1.21
Vol. of air required=1.21x2 m3=2.420m3
22.4 m3 of air weighs 28.949 kg
2.420 m3 of air will weigh =`2.420/22.4xx28.949=3.12 "kg"`
Wt. of air required=3.12kg.
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