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A geometric progression has common ratio = 3 and last term = 486. If the sum of its terms is 728; find its first term. - Mathematics

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प्रश्न

A geometric progression has common ratio = 3 and last term = 486. If the sum of its terms is 728; find its first term.

योग

उत्तर

For a G.P.,

Common ratio, r = 3  ...(∵ r > 1)

Last term, l = 486

S = 728

`=> (lr - a)/(r - 1) = 728`

`=> (486 xx 3 - a)/(3 - 1) = 728`

`=> (1458 - a)/2 = 728`

`=>` 1458 – a = 1456

Hence, the first term is 2.

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Geometric Progression - Finding Sum of Their First ‘N’ Terms
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Geometric Progression - Exercise 11 (D) [पृष्ठ १६१]

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सेलिना Mathematics [English] Class 10 ICSE
अध्याय 11 Geometric Progression
Exercise 11 (D) | Q 6 | पृष्ठ १६१
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