Question

A glass flask is filled up to a mark with 50 cc of mercury at 18°C. If the flask and contents are heated to 38°C, how much mercury will be above the mark? (α for glass is 9 × 10^-6/°C and coefficient of real expansion of mercury is 180 × 10^-6/°C)

विकल्प

• 0.85 cc

• 0.46 cc

• 0.153 cc

• 0.05 cc

Answer 1

0.153 cc

Explanation:

The difference between the volume of mercury and the flask due to volume expansion is given by

ΔV = V₀ [γ_L - γ_g]

Δθ = V [γ_L - 3α_g] Δθ

= 50 [180 × 10^-6 - 3 × 9 × 10^-6] (38 - 18)

= 0.513 cc