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Question
A glass flask is filled up to a mark with 50 cc of mercury at 18°C. If the flask and contents are heated to 38°C, how much mercury will be above the mark? (α for glass is 9 × 10-6/°C and coefficient of real expansion of mercury is 180 × 10-6/°C)
Options
0.85 cc
0.46 cc
0.153 cc
0.05 cc
MCQ
Solution
0.153 cc
Explanation:
The difference between the volume of mercury and the flask due to volume expansion is given by
ΔV = V0 [γL - γg]
Δθ = V [γL - 3αg] Δθ
= 50 [180 × 10-6 - 3 × 9 × 10-6] (38 - 18)
= 0.513 cc
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Thermal Expansion
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