हिंदी

A horizontal circular platform of mass 100 kg is rotating at 5 r.p.m. about vertical axis passing through its centre. A child of mass 20 kg is standing on the edge of platform. -

Advertisements
Advertisements

प्रश्न

A horizontal circular platform of mass 100 kg is rotating at 5 r.p.m. about vertical axis passing through its centre. A child of mass 20 kg is standing on the edge of platform. If the child comes to the centre of platform then the frequency of rotation will become ______.

विकल्प

  • 7 r.p.m.

  • 9 r.p.m

  • 5 r.p.m

  • 12 r.p.m

MCQ
रिक्त स्थान भरें

उत्तर

A horizontal circular platform of mass 100 kg is rotating at 5 r.p.m. about vertical axis passing through its centre. A child of mass 20 kg is standing on the edge of platform. If the child comes to the centre of platform then the frequency of rotation will become 7 r.p.m.

Explanation:

`(1/2 "Mr"^2 + "mr"^2)omega_1 = 1/2 "Mr"^2 omega_2`

`therefore omega_2 = ((1/2 "Mr"^2 + "mr"^2)omega_1)/(1/2 "Mr"^2)`

`= ((1/2 "M + m")omega_1"r"^2)/(1/2 "Mr"^2)`

`= (50 + 20)/50 xx 5`

`= (70 xx 5)/50`

= 7 r.p.m.

shaalaa.com
Applications of Uniform Circular Motion
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×