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A horizontal circular platform of mass 100 kg is rotating at 5 r.p.m. about vertical axis passing through its centre. A child of mass 20 kg is standing on the edge of platform. -

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Question

A horizontal circular platform of mass 100 kg is rotating at 5 r.p.m. about vertical axis passing through its centre. A child of mass 20 kg is standing on the edge of platform. If the child comes to the centre of platform then the frequency of rotation will become ______.

Options

  • 7 r.p.m.

  • 9 r.p.m

  • 5 r.p.m

  • 12 r.p.m

MCQ
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Solution

A horizontal circular platform of mass 100 kg is rotating at 5 r.p.m. about vertical axis passing through its centre. A child of mass 20 kg is standing on the edge of platform. If the child comes to the centre of platform then the frequency of rotation will become 7 r.p.m.

Explanation:

`(1/2 "Mr"^2 + "mr"^2)omega_1 = 1/2 "Mr"^2 omega_2`

`therefore omega_2 = ((1/2 "Mr"^2 + "mr"^2)omega_1)/(1/2 "Mr"^2)`

`= ((1/2 "M + m")omega_1"r"^2)/(1/2 "Mr"^2)`

`= (50 + 20)/50 xx 5`

`= (70 xx 5)/50`

= 7 r.p.m.

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Applications of Uniform Circular Motion
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