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Question
A horizontal circular platform of mass 100 kg is rotating at 5 r.p.m. about vertical axis passing through its centre. A child of mass 20 kg is standing on the edge of platform. If the child comes to the centre of platform then the frequency of rotation will become ______.
Options
7 r.p.m.
9 r.p.m
5 r.p.m
12 r.p.m
Solution
A horizontal circular platform of mass 100 kg is rotating at 5 r.p.m. about vertical axis passing through its centre. A child of mass 20 kg is standing on the edge of platform. If the child comes to the centre of platform then the frequency of rotation will become 7 r.p.m.
Explanation:
`(1/2 "Mr"^2 + "mr"^2)omega_1 = 1/2 "Mr"^2 omega_2`
`therefore omega_2 = ((1/2 "Mr"^2 + "mr"^2)omega_1)/(1/2 "Mr"^2)`
`= ((1/2 "M + m")omega_1"r"^2)/(1/2 "Mr"^2)`
`= (50 + 20)/50 xx 5`
`= (70 xx 5)/50`
= 7 r.p.m.