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A man is thrice as old as his son. Five years ago the man was four times as old as his son. Find their present ages. - Mathematics

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प्रश्न

A man is thrice as old as his son. Five years ago the man was four times as old as his son. Find their present ages.

योग

उत्तर

Let the present age of the son be x years.
As the man is 3 times as old as his son, the present age of the man will be (3x) years.

5 years ago:
Son's age = (x − 5) years
Man's age = (3x − 5) years

According to the question:
(3x − 5) = 4(x − 5)
or, 3x − 5 = 4 × x − 4 × 5 [On expanding the brackets]
or, 3x − 5 = 4x − 20
or, 20 − 5 = 4x − 3x [Transposing 3x to the R.H.S. and 20 to the L.H.S.]
or, x = 15
∴ Present age of the son = 15 years
Present age of the man = 3x = 3 × 15
= 45 years

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अध्याय 9: Linear Equation in One Variable - Exercise 9C [पृष्ठ १४५]

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आरएस अग्रवाल Mathematics [English] Class 6
अध्याय 9 Linear Equation in One Variable
Exercise 9C | Q 16 | पृष्ठ १४५

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