Advertisements
Advertisements
प्रश्न
A man leaves half his property to his wife, one-third to his son, and the remaining to his daughter. If the daughter's share is Rs. 15000, how much money did the man leave? How much money did his wife get?
उत्तर
Let the amount of property be x.
Daughter' share = `x = (1)/(2)x - (1)/(3)x`
As per the given condition,
`x - (1)/(2)x - (1)/(3)x` = 15000
⇒ `(6x - 3x - 2x)/(6)` = 15000
⇒ `x/(6)` = 15000
⇒ x = 90000
`(1)/(2)x = (90000)/(2)` = 45000
Hence, the amount of property he left was Rs.90000
and the amount his wife got was Rs.45000.
APPEARS IN
संबंधित प्रश्न
Solve the following equation:
`("x"+2)/9 = ("x" + 4)/11`
Solve: `"x"/5 + "2x" = 33`
The difference between a number and one- fourth of itself is 24, find the number.
Solve the following equation for the unknown: `(1)/(2)"p" + (3)/(4)"p"` = p - 3
The sum of three consecutive natural numbers is 216. Find the numbers
Divide 300 into two parts so that half of the one part is less than the other by 48.
A tap can fill a tank in 12 hrs while another tap can fill the same tank in x hours. Both the taps if opened together fill the tank in 6 hrs and 40 minutes. Find the time the second tap will take to fill the tank.
A 700g dry fruit pack costs Rs 72. It contains some cashew kernels and the rest as dry grapes. If cashew kernels cost Rs 96 per kg and dry grapes costs Rs 112 per kg, what were the quantities of the two dry fruits separately.
A 12 liter solution is `33(1)/(3)`% acid. How much water must be added to get the solution having 20% acid?
The measures of angles of a triangle are (9x - 5)°, (7x + 5)° and 20x°. Find the value of x. Also, show that the triangle is isosceles.