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प्रश्न
A metre scale of weight 50 gf can be balanced at 40 cm mark without any weight suspended on it.
- If this ruler is cut at its centre then state which part [0 to 50 cm or 50 to 100 cm] of the ruler will weigh more than 25 gf.
- What minimum weight placed on this metre ruler can balance this ruler when it is pivoted at its centre?
उत्तर
a. Because the scale of meters is not uniform, 0 to 50 cm would be heavier.
b. By principle of moments
50 × 10 = w × 50
w = 10 gf
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संबंधित प्रश्न
Draw a diagram of a block and tackle system of pulleys having a velocity ratio of 5. In your diagram indicate clearly the points of application and the directions of the load L and effort E. Also mark the tension T in each strand.
The velocity ratio of a single movable pulley is always 2.
The velocity ratio of a combination of n movable pulleys with a fixed pulley is always 2n.
The velocity ratio of a block and tackle system is always equal to the number of strands of the tackle supporting the load.
Copy and complete the labelled diagram connecting the two pulleys with a tackle to obtain Velocity Ratio= 2.
If Load = 48 kgf and efficiency is 80% then calculate:
- Mechanical Advantage.
- Effort needed to lift the load.
The adjacent diagram shows the movable block of a block and tackle system with effort in a convenient direction. From the diagram we can conclude that the number of pulleys used in the fixed block are ______.
In a block and tackle system, increase in the weight of the movable block ______ the efficiency of the pulley system.
