Advertisements
Advertisements
प्रश्न
A milk container of height 16 cm is made of metal sheet in the form of a frustum of a cone with radii of its lower and upper ends as 8 cm and 20 cm respectively . Find the cost of milk at the rate of ₹44 per litre which the container can hold.
उत्तर
Radius, r1 = 8 cm and r2 = 20 cm
Height, h = 16 cm
Volume of milk that the container can hold
\[V = \frac{1}{3}\pi h\left( r_1^2 + r_1 r_2 + r_2^2 \right)\]
\[V = \frac{1}{3}\pi \times 16\left( 8^2 + 8 \times 20 + {20}^2 \right)\]
\[V = 10459 . 42 {cm}^3 = 10 . 45942 \text { liters }\]
Cost of milk will be \[10 . 45942 \times 44 = \text { Rs }460 . 21\]
APPEARS IN
संबंधित प्रश्न
A drinking glass is in the shape of a frustum of a cone of height 14 cm. The diameters of its two circular ends are 4 cm and 2 cm. Find the capacity of the glass. [use π=22/7]
A heap of rice in the form of a cone of diameter 9 m and height 3.5 m. Find the volume of rice. How much canvas cloth is required to cover the heap ?
A bucket is in the form of a frustum of a cone and holds 28.490 litres of water . The radii of the top and bottom are 28 cm and 21 cm respectively . Find the height of the bucket .
A cone, a hemisphere and a cylinder stand on equal bases and have the same height. What is the ratio of their volumes?
A metallic sphere of radius 10.5 cm is melted and then recast into small cones, each of radius 3.5 cm and height 3 cm. The number of such cones is
A cone of height 20 cm and radius of base 5 cm is made up of modelling clay. A child reshapes it in the form of a sphere. Find the diameter of the sphere.
The radii of the circular ends of a solid frustum of a cone are 33 cm and 27 cm and its slant height is 10 cm. Find its total surface area. [Use π = 3.14.]
The height of a right circular cone is 20 cm. A small cone is cut off at the top by a plane parallel to the base. If its volume be `1/8` of the volume of the given cone, then at what height above the base is the section made?
A cylindrical pencil sharpened at one edge is combination of ______.
The curved surface area of a frustum of a cone is πl (r1 + r2), where `l = sqrt(h^2 + (r_1 + r_2)^2)`, r1 and r2 are the radii of the two ends of the frustum and h is the vertical height.
