Advertisements
Advertisements
प्रश्न
A cone, a hemisphere and a cylinder stand on equal bases and have the same height. What is the ratio of their volumes?
उत्तर
Let r be the radius of the base.
And h is the height.
Here, h = r.
Now,
The ratio of their volumes will be
Volume of cone: volume of hemisphere: volume of a cylinder
`1/3pir^2 h : 2/3pir^3 : pir^2 h `
`V_1 :V_2 :V_3 = 1/3pir^3 : 2/3 pir^3 : pir^3`
Hence , `V_1 : V_2 :V_3 = 1:2:3`
APPEARS IN
संबंधित प्रश्न
A solid toy s in the form of a hemisphere surrounded by a right circular cone . The height of cone is 4 cm and the diameter of the base is 8 cm . Determine the volume of the toy. If a cube circumscribes the toy , then find the difference of the volumes of cube and the toy .
An oil funnel of tin sheet consists of a cylindrical portion 10 cm long attached to a frustum of a cone. If the total height be 22 cm, the diameter of the cylindrical portion 8 cm and the diameter of the top of the funnel 18 cm, find the area of the tin required.(Use π = 22/7).
A solid consists of a circular cylinder with an exact fitting right circular cone placed at the top. The height of the cone is h. If the total volume of the solid is 3 times the volume of the cone, then the height of the circular is
A right triangle with sides 3 cm, 4 cm and 5 cm is rotated about the side of 3 cm to form a cone. The volume of the cone so formed is
The diameters of the ends of a frustum of a cone are 32 cm and 20 cm. If its slant height is 10 cm, then its lateral surface area is
A metallic spherical shell of internal and external diameters 4 cm and 8 cm, respectively, is melted and recast in the form of a cone of base diameter 8 cm. The height of the cone is ______.
The circular ends of a bucket are of radii 35 cm and 14 cm and the height of the bucket is 40 cm. Its volume is
In a right circular cone, the cross-section made by a plane parallel to the base is a ______.
An open metallic bucket is in the shape of a frustum of a cone, mounted on a hollow cylindrical base made of the same metallic sheet. The surface area of the metallic sheet used is equal to curved surface area of frustum of a cone + area of circular base + curved surface area of cylinder.
