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A Mixture of Hydrogen and Chlorine Occupying 36 Cm3 Was Exploded. on Shaking It with Water, 4cm3 of Hydrogen Was Left Behind. Find the Composition of the Mixture. - Chemistry

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प्रश्न

A mixture of hydrogen and chlorine occupying 36 cm3 was exploded. On shaking it with water, 4cmof hydrogen was left behind. Find the composition of the mixture.

संख्यात्मक

उत्तर

\[\ce{H2 + Cl2 → 2HCl}\]

1vol. : 1vol. `→` 2vol.

As, 4 cm3 of hydrogen was left behind, hence, 36 − 4 = 32 cm3 of mixture of hydrogen and chlorine exploded.

As, 1 Vol. of hydrogen requires 1 Vol. of oxygen

∴ 16 cm3 hydrogen requires 16 cm3 of oxygen

∴ Mixture is 20 cm3 (i.e., 16 + 4) of hydrogen and 16 cm3 of chlorine.

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Fundamental Laws of Gases - Gay Lussac’s Law of Combining Volumes
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Mole concept and Stoichiometry - Exercise 5A [पृष्ठ ७५]

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सेलिना Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
Exercise 5A | Q 15 | पृष्ठ ७५

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