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प्रश्न
What volume of air (containing 20% O2 by volume) will be required to burn completely 10 cm3 of methane?
\[\ce{CH4 + 2O2 → CO2 + 2H2O}\]
\[\ce{2C2H2 + 5O2 -> 4CO2 + 2H2O}\]
उत्तर
Methane + Oxygen
\[\ce{\underset{10 cm^3}{\underset{1 V}{CH4} + \underset{2 V}{2O2}} -> CO2 + 2H2O}\]
∴ Volume of \[\ce{O2}\] required = 10 × 2 = 20 cm3
∴ Volume of air = 20 × 5 = 100 cm3
∴ 20 cc of \[\ce{O2}\] is contained in 100 cm3 of air.
Acetylene + Oxygen
\[\ce{\underset{10 cm^3}{\underset{2 V}{2C2H2} + \underset{5 V}{5O2}} -> 4CO2 + 2H2O}\]
∴ Volume of \[\ce{O2}\] required = `5/2 xx 10 = 25` cm3
But 20 cm3 \[\ce{O2}\] is contained in air = 100 cm3
∴ 25 cm3 \[\ce{O2}\] is contained in air
= `100/20 xx 25`
= 125 cm3
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