Advertisements
Advertisements
प्रश्न
A model of a ship is made to a scale of 1:500. Find: The length of the ship, if length of the model is 1.2.
उत्तर
Scale = 1:500
The length of the model = 11.2m
The actual length
= 1.2 x 500
= 600m.
APPEARS IN
संबंधित प्रश्न
In figure, ∠BAC = 90º and segment AD ⊥ BC. Prove that AD2 = BD × DC.
ABCD is parallelogram and E is a point on BC. If the diagonal BD intersects AE at F, prove that AF × FB = EF × FD.
Select the appropriate alternative.
In ∆ABC and ∆PQR, in a one to one correspondence \[\frac{AB}{QR} = \frac{BC}{PR} = \frac{CA}{PQ}\]
A triangle LMN has been reduced by scale factor 0.8 to the triangle L' M' N'. Calculate: the length of M' N', if MN = 8 cm.
On a map drawn to a scale of 1 : 2,50,000; a triangular plot of land has the following measurements : AB = 3 cm, BC = 4 cm and ∠ABC = 90°.
Calculate : the actual lengths of AB and BC in km.
In the following figure, point D divides AB in the ratio 3 : 5. Find :
- `(AE)/(EC)`
- `(AD)/(AB)`
- `(AE)/(AC)`
Also, if: - DE = 2.4 cm, find the length of BC.
- BC = 4.8 cm, find the length of DE.
In fig.DE || BC ,AD = 1 cm and BD = 2 cm. what is the ratio of the ar(ΔABC) to the ar (ΔADE)?
In ΔABC, point D divides AB in the ratio 5:7, Find: `"AD"/"AB"`
A map is drawn to scale of 1:20000. Find: The distance on the map representing 4km
A vertical stick of length 6 m casts a shadow 400 cm long on the ground and at the same time a tower casts a shadow 28 m long. Using similarity, find the height of the tower
