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प्रश्न
A pair of dice is thrown. Find the probability of getting a sum of 10 or more, if 5 appears on the first dice.
उत्तर
In throwing a dice, total possible outcome = {1, 2, 3, 4, 5, 6}
n(S) = 6
For two dice, n(S) = 6 × 6 = 36
Favorable cases where the sum is 10 or more with 5 on 1st die = {(5, 5),(5, 6)}
Event of getting the sum is 10 or more with 5 on 1st die = n(E) = 2
Probability of getting a sum of 10 or more with 5 on 1st die = `(n(E))/(n(S))`
= `2/36`
= `1/18`
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