Question

A parallelogram has sides of 15 cm and 12 cm; if the distance between the 15 cm sides is 6 cm; find the distance between 12 cm sides.

Answer 1

Base, AB = 15 cm

Distance between 15 cm sides

i.e. height DP = 6 cm

∴ Area of ||gm = Base × height

= AB × DP

 = 15 × 6 = 90 cm²

Let BQ be the distance between 12 cm sides

∴ AD × BQ = area of ||gm ABCD

∴ 12 × BQ = 90

BQ = ${\displaystyle \frac{90}{12}}$

BQ = ${\displaystyle \frac{15}{2}=7.5}$ cm