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प्रश्न
A piece of wood of mass m is floating erect in a liquid whose density is ρ. If it is slightly pressed down and released, then executes simple harmonic motion. Show that its time period of oscillation is T = `2π sqrt("m"/("Ag"ρ))`
उत्तर
Spring factor of liquid (k) = Agρ
Inertia factor of a piece of wood = m
Time period T = `2π sqrt("Inertia factor"/"Spring factor")`
T = `2π sqrt("m"/("Ag"ρ))`
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