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A pulse of light of duration 10-6 s is absorbed completely by a small object initially at rest. If the power of the pulse is 60 x 10-3 W, calculate the final momentum of the object. - Physics

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प्रश्न

A pulse of light of duration 10-6 s is absorbed completely by a small object initially at rest. If the power of the pulse is 60 x 10-3 W, calculate the final momentum of the object.

संख्यात्मक

उत्तर

Duration of the absorption of light pulse, t = 10-6s

Power of the pulse P = 60 x 10-3 W

Final momentum of the object, P = `"U"/"c"`

Velocity of light, C = 3 x 108

Energy U = power x time

Momentum, P = `(60 xx 10^-3 xx 10^-6)/(3 xx 10^8)`

P = 20 × 10-17 kg m s-1

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अध्याय 5: Electromagnetic waves - Evaluation [पृष्ठ २८४]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 5 Electromagnetic waves
Evaluation | Q IV. 3. | पृष्ठ २८४
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