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प्रश्न
Let an electromagnetic wave propagate along the x-direction, the magnetic field oscillates at a frequency of 1010 Hz and has an amplitude of 10-5 T, acting along the y – direction. Then, compute the wavelength of the wave. Also write down the expression for the electric field in this case.
उत्तर
Frequency of electromagnetic wave, v = 1010 Hz
Amplitude of Oscillating magnetic field, B0 = 10-5 T
Wave length of the wave, λ = `"C"/"f" = (3 xx 10^8)/10^10 = 3 xx 10^-2`m
Amplitude of oscillating electric field, E0 = B0 C
C = `"E"_0/"B"_0`
E0 = 10-5 × 3 × 108
E0 = 3 × 103 = NC-1
Experession for the electric field in Oscillating wave
E = E0 sin (kx -wt)
K = `(2pi)/lambda = (2 xx 3.14)/(3 xx 10^-2) = 209 xx 10^2`
W = 2πƒ = 2 × 3.14 x 1010 = 6.28 × 1010
`vec"E"` = 3 x 103 sin (2.09 × 102 x – 6.28 × 1010 t) `hat"i"` NC-1.
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