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Let an electromagnetic wave propagate along the x direction, the magnetic field oscillates at a frequency of 1010 Hz and has an amplitude of 10-5 T, acting along the y – direction. - Physics

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प्रश्न

Let an electromagnetic wave propagate along the x-direction, the magnetic field oscillates at a frequency of 1010 Hz and has an amplitude of 10-5 T, acting along the y – direction. Then, compute the wavelength of the wave. Also write down the expression for the electric field in this case.

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उत्तर

Frequency of electromagnetic wave, v = 1010 Hz

Amplitude of Oscillating magnetic field, B0 = 10-5 T

Wave length of the wave, λ = `"C"/"f" = (3 xx 10^8)/10^10 = 3 xx 10^-2`m

Amplitude of oscillating electric field, E0 = B0 C

C = `"E"_0/"B"_0`

E0 = 10-5 × 3 × 108

E0 = 3 × 103 = NC-1

Experession for the electric field in Oscillating wave

E = E0 sin (kx -wt)

K = `(2pi)/lambda = (2 xx 3.14)/(3 xx 10^-2) = 209 xx 10^2`

W = 2πƒ = 2 × 3.14 x 1010 = 6.28 × 1010

`vec"E"`  = 3 x 103 sin (2.09 × 102 x – 6.28 × 1010 t) `hat"i"` NC-1.

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अध्याय 5: Electromagnetic waves - Evaluation [पृष्ठ २८४]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 5 Electromagnetic waves
Evaluation | Q IV. 4. | पृष्ठ २८४
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