Advertisements
Advertisements
प्रश्न
A ray of light passes through a prism of refractive index `sqrt2` as shown in the figure. Find:
- The angle of incidence (∠r2) at face AC.
- The angle of minimum deviation for this prism.
उत्तर
(i) Since at point N, the angle of refraction is 90°, then ∠r2 is the critical angle for the glass-air pair of media.
sin ∠r2 = `1/μ = 1/sqrt2`
∴ ∠r2 = `sin^-1(1/sqrt2)` = 45°
(ii) μ = `sin(("A" + δ_"m")/2)/(sin "A"/2)`
Or, `sqrt2 = sin ((60^circ + δ_"m")/2)/(sin 60^circ/2)`
Or, `sqrt2 = sin (30^circ + δ_"m"/2)/(1/2)`
Or, 0.7 = `sin(30^circ + δ_"m"/2)`
Or, sin−1 0.7 = `30^circ + δ_"m"/2`
Or, 44.4° = `30^circ + δ_"m"/2`
∴ δm = 28.8°
APPEARS IN
संबंधित प्रश्न
In the following figure, show two rays A and B travelling from water to air. If the critical angle for water- air surface is 48°, complete the ray diagram showing the refracted rays for each. State conditions when the ray will suffer total internal reflection.
How does a ray of light bend when it travels from rarer to denser medium
Why do diamonds sparkle?
Write down the relationship between the critical angle and the refractive index of the medium.
Answer the following question.
What are the advantages of optical fibre communication over electronic communication?
Total internal reflection can take place only if light is travelling from ______.
Optical fibre communication uses the principle of ______.
State the condition under which total internal reflection occurs. Give the mathematical expression for total internal reflection.
A ray of light passes from vacuum into a medium of refractive index µ, the angle of incidence is found to be twice the angle of refraction. Then the angle of incidence is ______.
State two differences between normal reflection and total internal reflection.
