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प्रश्न
A refrigerator is to maintain eatables kept inside at 9°C. If the room temperature is 36° C, calculate the coefficient of performance.
उत्तर १
Temperature inside the refrigerator, T1 = 9°C = 282 K
Room temperature, T2 = 36°C = 309 K
Coefficient of performance = `T_1/(T_2 -T_2)`
`= 282/(309 - 282)`
= 10.44
Therefore, the coefficient of performance of the given refrigerator is 10.44.
उत्तर २
Here `T_1 = 36 ""^@C = (36 + 273) K = 309 K`
`T_2 = 9 ^@C = (9 + 273) K = 282 K`
Coefficient of performance = `E = T_1/(T_1 - T_2) = 282/(309 - 282) = 282/ 27 = 10.4`
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