Question

A shepherd has 200 sheep with him. Find the number of sheep with him after 2 years if the increase in number of sheep is 10% every year.

Answer 1

P = Number of sheep initially = 200

R = Rate of increase in sheep = 10% p.a.

N = 2 years

A = number of sheep after 2 years.

A = `"P"(1 + "R"/100)^"N"`

= `200(1 + 10/100)^2`

= `200((100 + 10)/100)^2`

= `200 xx (110/100)^2`

= `200 xx 110/100 xx 110/100`

= `(220 xx 110)/100`

= `24200/100`

= 242 sheeps