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प्रश्न
A simple pendulum of frequency n falls freely under gravity from a certain height from the ground level. Its frequency of oscillation.
विकल्प
Remain unchanged
> n
Becomes zero
Becomes infinite
MCQ
उत्तर
Becomes zero
Explanation:
For free fall geff = 0, so frequency of oscillation will be zero
f = `1/(2π) sqrt("g"_"eff"/λ)`
f = 0
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