Question

A simple pendulum of frequency n falls freely under gravity from a certain height from the ground level. Its frequency of oscillation.

Options

• Remain unchanged

• > n

• Becomes zero

• Becomes infinite

Answer 1

Becomes zero

Explanation:

For free fall g_eff = 0, so frequency of oscillation will be zero

f = `1/(2π) sqrt("g"_"eff"/λ)`

f = 0