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A Solid is Composed of a Cylinder with Hemispherical Ends. If the Length of the Whole Solid is 108 Cm and the Diameter of the Cylinder is 36 Cm, Find the Cost of Polishing - Mathematics

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प्रश्न

A solid is composed of a cylinder with hemispherical ends. If the length of the whole solid is 108 cm and the diameter of the cylinder is 36 cm, find the cost of polishing the surface at the rate of 7 paise per cm2 .

संक्षेप में उत्तर

उत्तर

 

Height of the cylinder = height of entire solid - height of sphere 1 - height of sphere 2
= 108 - 18 - 18

= 108 − 36

= 72 cm

r = 18 cm

C.S.A. of cylinder

\[= 2\pi r h\]

\[ = 2\pi \times 18 \times 72\]

\[ = 8138 . 88 {cm}^2\]

C.S.A. of 2 hemispheres = surface area of a sphere

\[= 4 \pi r^2 \]

\[ = 4\pi \left( 18 \right)^2 \]

\[ = 4069 . 44 {cm}^2\]

Surface area of solid

= 8138.88 + 4069.44 
= 12208.32 cm2

Cost of polishing 1 cm2 = 7 paise = 0.07 Rs

Total cost

\[= 12208 . 32 \times 0 . 07\]

\[ = \text { Rs } 854 . 58\]

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अध्याय 14: Surface Areas and Volumes - Exercise 14.3 [पृष्ठ ८२]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 14 Surface Areas and Volumes
Exercise 14.3 | Q 31 | पृष्ठ ८२
आरडी शर्मा Mathematics [English] Class 10
अध्याय 14 Surface Areas and Volumes
Exercise 14.3 | Q 44 | पृष्ठ ८३

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