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प्रश्न
A solution is prepared by dissolving 9.25 g of non-volatile solute in 450 mL of water. It has an osmotic pressure of 350 mm of Hg at 27°C. Assuming the solute is non-electrolyte, determine its molecular mass. (R = 0.0821 lit atm K-1 mol-1)
उत्तर
`"W"_"B" = 9.25 "g"`
V = 450 mL = 0.450 L
π = 350 mm = `350/760` atm
T = 273 + 27 = 300 K
MB = ?
R = 0.0821 L atm K-1 mol-1
π = `"n"_"B"/"V" xx "R" xx "T" = "W"_"B"/("M"_"B"/"V") xx "R" xx "T"`
`350/760 = 9.25/("M"_"B"/0.45) xx 0.0821 xx 300`
`9.25/("M"_"B") = 350/760 xx 0.45/(0.0821 xx 300)`
`("M"_"B") = (9.25 xx 760 xx 0.0821 xx 300)/(350 xx 0.45)`
`("M"_"B") = 1099.35` amu
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