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प्रश्न
A spring balance has a scale that reads from 0 to 50 kg. The length of the scale is 20 cm. A body suspended from this balance, when displaced and released osillates with a period of 0.6 sec. What is the weight of the body?
संख्यात्मक
उत्तर
Given: m = 50 kg, x = 20 cm= 0.2 m, T = 0.6 sec
`T=2pisqrt(m/k)`
Since, f = mg
`=50xx9.8=kx`
`k=(50xx9.8)/0.2=2450Nm^-1`
From formula,
`m=(T^2k)/(4pi^2) = ((0.6)^2xx2450)/(4xx9.87)`
`=22.34 kg`
`W = mg=22.34xx9.8 = 219N`
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