Question

A spring balance has a scale that reads from 0 to 50 kg. The length of the scale is 20 cm. A body suspended from this balance, when displaced and released osillates with a period of 0.6 sec. What is the weight of the body?

Answer 1

Given: m = 50 kg, x = 20 cm= 0.2 m, T = 0.6 sec

`T=2pisqrt(m/k)`

Since, f = mg

`=50xx9.8=kx`

`k=(50xx9.8)/0.2=2450Nm^-1`

From formula,

`m=(T^2k)/(4pi^2) = ((0.6)^2xx2450)/(4xx9.87)`

`=22.34 kg`

`W = mg=22.34xx9.8 = 219N`