Question

A spring breaks under tension of 10 kg wt.If the string is used to revolve a body of mass 1.2 kg in a horizontal circle. of radius 50 cm, what is the maximum speed with which a body can be revolved?

Answer 1

Given: Tension = 10 kg wt = 10 × 9.8 N

∴ f_cp = 98 N, m = 1.2 m

r = 50 cm = 50 x 10^-2 m,

To find: v_max =?

We have,

`f_(cp) = (mv_max^2)/r`

∴ `v_max^2 = (r. f_cp)/m`

`= (50 xx 10^-2 xx 98)/1.2`

∴ `v_max^2 = 4083.3 xx 10^-2`

`v_max = 6.389 m//s`