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A stone of mass 3 kg attached at one end of a 2m long string is whirled in horizontal circle. The string makes an angle of 45° with the vertical then the centripetal force acting on the string is -

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प्रश्न

A stone of mass 3 kg attached at one end of a 2m long string is whirled in horizontal circle. The string makes an angle of 45° with the vertical then the centripetal force acting on the string is ______.

(g = 10 m/s2 , tan 45° = 1)

विकल्प

  • 20 N

  • 30 N

  • 10 N

  • 40 N

MCQ
रिक्त स्थान भरें

उत्तर

A stone of mass 3 kg attached at one end of a 2m long string is whirled in horizontal circle. The string makes an angle of 45° with the vertical then the centripetal force acting on the string is 20 N.

Explanation:

For conical pendulum `tan theta="v^2"/"rg"`

`therefore"v"^2/r=g tantheta=10xxtan45^circ=10xx1=10  "m/s"^2`

Centripetal force `F="mv"^2/r=2xx10=20  N`

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