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Question
A stone of mass 3 kg attached at one end of a 2m long string is whirled in horizontal circle. The string makes an angle of 45° with the vertical then the centripetal force acting on the string is ______.
(g = 10 m/s2 , tan 45° = 1)
Options
20 N
30 N
10 N
40 N
MCQ
Fill in the Blanks
Solution
A stone of mass 3 kg attached at one end of a 2m long string is whirled in horizontal circle. The string makes an angle of 45° with the vertical then the centripetal force acting on the string is 20 N.
Explanation:
For conical pendulum `tan theta="v^2"/"rg"`
`therefore"v"^2/r=g tantheta=10xxtan45^circ=10xx1=10 "m/s"^2`
Centripetal force `F="mv"^2/r=2xx10=20 N`
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