Question

A straight wire carrying current 'I' is bent into a semi-circular arc of radius 'r', as shown. The magnitude of magnetic field at point 'O' due to semi-circular arc is (µ₀ = Permeability of free space) ____________.

विकल्प

• `(mu_0 "I")/"r"`

• `(mu_0 "I")/(4"r")`

• `(mu_0 "I")/"r"^2`

• `(mu_0 "I")/(2"r")`

Answer 1

A straight wire carrying current 'I' is bent into a semi-circular arc of radius 'r', as shown. The magnitude of magnetic field at point 'O' due to semi-circular arc is `(mu_0 "I")/(4"r")`.

Explanation:

`"B" = (mu_0 "I")/(4"r")`