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Question
A straight wire carrying current 'I' is bent into a semi-circular arc of radius 'r', as shown. The magnitude of magnetic field at point 'O' due to semi-circular arc is (µ0 = Permeability of free space) ____________.
Options
`(mu_0 "I")/"r"`
`(mu_0 "I")/(4"r")`
`(mu_0 "I")/"r"^2`
`(mu_0 "I")/(2"r")`
MCQ
Diagram
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Solution
A straight wire carrying current 'I' is bent into a semi-circular arc of radius 'r', as shown. The magnitude of magnetic field at point 'O' due to semi-circular arc is `(mu_0 "I")/(4"r")`.
Explanation:
`"B" = (mu_0 "I")/(4"r")`
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Magnetic Field Due to a Current: Biot-savart Law
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