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प्रश्न
A team of medical students doing their internship have to assist during surgeries at a city hospital. The probabilities of surgeries rated as very complex, complex, routine, simple or very simple are respectively, 0.15, 0.20, 0.31, 0.26, .08. Find the probabilities that a particular surgery will be rated neither very complex nor very simple
उत्तर
Let E1, E2, E3, E4 and E5 be the events that the surgeries are rated as very complex, complex, routine, simple and very simple respectively.
∴ P(E1) = 0.15
P(E2) = 0.20
P(E3) = 0.31
P(E4) = 0.26
And P(E5) = 0.08
P(neither very complex nor very simple) = P(E'1 ∩ E'5)
= P(E1 ∪ E5)' = 1 – P(E1 ∪ E5)
= 1 – [P(E1) + P(E5)]
= 1 – [0.15 + 0.08]
= 1 – 0.23
= 0.77
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