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A Train Moving with a Velocity of 20 M S-1 is Brought to Rest by Applying Brakes in 5 S. Calculate the Retardation. - Physics

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प्रश्न

A train moving with a velocity of 20 m s-1 is brought to rest by applying brakes in 5 s. Calculate the retardation.

संख्यात्मक

उत्तर

Given, Initial velocity (u) = 20 m/s-1

Final velocity (v) = 0

Time taken (t) = 5 s

Let acceleration be 'a'.

Using the first equation of motion,

∴ v = u + at

∴ 0 = 20 + 5a

∴ a = -4 m/s-2     ...(since negative acceleration is called the retardation)

Thus, retardation = 4 m/s-2 

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अध्याय 2: Motion in One Dimension - Exercise 2 (C) [पृष्ठ ५४]

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सेलिना Concise Physics [English] Class 9 ICSE
अध्याय 2 Motion in One Dimension
Exercise 2 (C) | Q 6 | पृष्ठ ५४
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