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प्रश्न
A train travels a distance of 300kms at a constant speed. If the speed of the train is increased by 10km/ hour, the j ourney would have taken 1 hour less. Find the original speed of the train.
उत्तर
Let the speed of the train be S.
D=300Km, Time = Distance/ Speed. Time difference= ! Hours
Hence, in these two conditions,
`300/"S" - 300/("S" + 10) = 1`
⇒ 300 (S+ 10) - 3005= S (S+ 10)
⇒ s2 + 105 - 3000 = 0
⇒ S2 + 605 -505 - 3000 = 0
⇒ S (S - 60) - 50 (S - 60) = 0
⇒ (S + 60) (S - 50) = 0
As the speed can't be negative, S = 50 km/ hr .
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