Advertisements
Advertisements
प्रश्न
A TV transmission tower antenna is at a height of 20 m. How much service area can it cover if the receiving antenna is (i) at ground level, (ii) at a height of 25 m? Calculate the percentage increase in area covered in case (ii) relative to case (i).
उत्तर
(i) Range = `sqrt(2 xx 6.4 xx 10^6 xx 20)` = 16 km
Area covered = 803.84 km2
(ii) Range = `sqrt(2 xx 6.4 xx 10^6 xx 20) + sqrt(2 xx 6.4 xx 10^6 xx 25)`
= (16 + 17.9) km2
= 33.9 km
Area covered = 3608.52 km2
∴ Percentage increase in area = `((3608.52 - 803.84))/803.84 xx 100`
= 348.9%
APPEARS IN
संबंधित प्रश्न
The carrier wave is given by
C(t) = 2sin(8πt) volt.
The modulating signal is a square wave as shown. Find modulation index.
Why is Modulation index kept low?
A carrier wave of peak voltage 15 V is used to transmit a message signal. Find the peak voltage of the modulating signal in order to have a modulation index of 60%
State any two types of modulation
In the block diagram of a simple modulator for obtaining an AM signal, shown in the figure, identify the boxes A and B. Write their function.
In the given block diagram of a receiver, identify the boxes labeled as X and Y and write their functions.
Given modulation index physical significance .For an amplitude modulated wave, the maximum amplitude is found to be 10 V while the minimum amplitude is 2 V. Determine the modulation index μ ?
Answer the following question.
Why a signal transmitted from a TV tower cannot be received beyond a certain distance? Write the expression for the optimum separation between the receiving and the transmitting antenna.
A 25 m long antenna is mounted on an antenna tower. The height of the antenna tower is 75 m. The wavelength (in meter) of the signal transmitted by this antenna would be ______.
A transmitting antenna has a height of 320 m and that of receiving antenna is 2000 m. The maximum distance between them for satisfactory communication in line of sight mode is 'd'. The value of 'd' is ______ km.