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प्रश्न
A wire is cut into several small pieces. Each of the small pieces is bent into a square of side 2 cm. If the total area of the small squares is 28 square cm, what was the original length of the wire?
उत्तर
Given, side of square made by bending a small piece of wire = 2 cm
And total area of the small squares made by benting small pieces of wire = 28 sq cm
Now, number of small squares = `"Total area of small squares"/"Area of one small squares"`
= `28/(2 xx 2)` ......[∵ Area of square = Side × Side]
= `28/4` = 7
Now, perimeter of a small square = 4 × Side
= 4 × 2
= 8 cm
Perimeter of 7 such small squares = Perimeter of one small square × 7
= 8 × 7
= 56 cm
∴ Original length of wire = Perimeter of 7 small squares = 56 cm
Hence, the original length of wire is 56 cm.
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