Question

A wooden block of mass 'M' moves with velocity 'v ' and collides with another block of mass '4M' which is at rest. After collision, the block of mass 'M' comes to rest. The coefficient of restitution will be ______.

विकल्प

• 0.25

• 0.15

• 0.05

• 0.30

Answer 1

A wooden block of mass 'M' moves with velocity 'v ' and collides with another block of mass '4M' which is at rest. After collision, the block of mass 'M' comes to rest. The coefficient of restitution will be 0.25.

Explanation:

Mv + 0 = 0 + 4MV

`therefore V=("Mv")/(4"M")="v"/4`

`e="v/4"/"v"=1/4=0.25`