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Question
A wooden block of mass 'M' moves with velocity 'v ' and collides with another block of mass '4M' which is at rest. After collision, the block of mass 'M' comes to rest. The coefficient of restitution will be ______.
Options
0.25
0.15
0.05
0.30
MCQ
Fill in the Blanks
Solution
A wooden block of mass 'M' moves with velocity 'v ' and collides with another block of mass '4M' which is at rest. After collision, the block of mass 'M' comes to rest. The coefficient of restitution will be 0.25.
Explanation:
Mv + 0 = 0 + 4MV
`therefore V=("Mv")/(4"M")="v"/4`
`e="v/4"/"v"=1/4=0.25`
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