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प्रश्न
An electron of charge 'e' is revolving in a fixed orbit of radius 'r' with frequency 'f'. Its magnetic dipole moment is ____________.
विकल्प
`pi^2 "efr"`
`pi "efr"^2`
`pi "efr"`
`pi^2 "efr"^2`
MCQ
रिक्त स्थान भरें
उत्तर
An electron of charge 'e' is revolving in a fixed orbit of radius 'r' with frequency 'f'. Its magnetic dipole moment is `pi "efr"^2`.
Explanation:
Magnetic dipole moment M = IA.
For a revolving electron I = ef and A = `pi"r"^2`
`therefore "M" = pi"efr"^2`
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