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प्रश्न
An element A burns with golden flame in air. It reacts with another element B, atomic number 17 to give a product C. An aqueous solution of product C on electrolysis gives a compound D and liberates hydrogen. Identify A, B, C and D. Also write down the equations for the reactions involved.
उत्तर
Sodium when burnt in air, burns with a golden flame so, element A is sodium. Since element B has an atomic number of 17 so, it is chlorine. When sodium reacts with chlorine it forms sodium chloride.
`2"Na" + "Cl"_2 -> 2"NaCl"`
When an aqueous solution of sodium chloride is electrolysed it liberates hydrogen and chlorine gas and another aqueous product sodium hydroxide so, the compound D is sodium hydroxide.
`2"NaCl" + 2"H"_2"O" -> 2"NaOH" + "H"_2 + "Cl"_2`
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