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प्रश्न
An expression for oscillating electric field in a plane electromagnetic wave is given as Ez = 300 sin(5π × 103x - 3π × 1011t)Vm-1 Then, the value of magnetic field amplitude will be ______. (Given: speed of light in Vacuum c = 3 × 108 ms-1)
विकल्प
1 × 10-6 T
5 × 10-6 T
18 × 109 T
21 × 109 T
MCQ
रिक्त स्थान भरें
उत्तर
An expression for oscillating electric field in a plane electromagnetic wave is given as Ez = 300 sin(5π × 103x - 3π × 1011t)Vm-1 Then, the value of magnetic field amplitude will be 5 × 10-6 T. (Given: speed of light in Vacuum c = 3 × 108 ms-1)
Explanation:
We know that,
B0 = `"E"_0/"V"=300/("w"/"k")`
= `(300xx5pixx10^3)/(3pixx10^11)`
= 5 × 10-6 T
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